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crossjoin.rb
This Ruby code snippet demonstrates the use of the product
method in combination with other methods to create a collection of all possible combinations of elements from three arrays. The product
method takes multiple arrays as arguments and returns a new array that contains all possible combinations of elements from the input arrays.
The first line of code, a = ('a'..'c').to_a
, creates an array containing the letters ‘a’, ‘b’, and ‘c’. The second line, b = 2.times.to_a
, creates an array containing two elements, 0 and 1. The third line, c = [{}]
, creates an empty hash.
The final line of code, a.product(b, c)
, uses the product
method to create a new array that contains all possible combinations of elements from a
, b
, and c
. This will result in a new array with 6 elements, each consisting of a combination of an element from a
, b
, and c
.
For example, if the input arrays are ['a', 'b', 'c']
, [0, 1]
, and {}
, then the output array would contain the following combinations:
[['a', 0, {}], ['a', 1, {}], ['b', 0, {}], ['b', 1, {}], ['c', 0, {}], ['c', 1, {}]]
Note that the output array will contain a combination of each element from a
, b
, and c
, in all possible orders.
Ruby code snippet
a = ('a'..'c').to_a
#=> ["a", "b", "c"]
b = 2.times.to_a
#=> [0, 1]
c = [{}]
#=> [{}]
a.product(b, c)
#=>
[["a", 0, {}],
["a", 1, {}],
["b", 0, {}],
["b", 1, {}],
["c", 0, {}],
["c", 1, {}]]
Executed with Ruby 3.4.4
.